Tic-Tac-Toe

Tacos Before Vatos ......!

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Inspiration

Since we are spending most of our time outdoors now I thought of making one set of Tic Tac Toe for outside play. It came out lovely and Sofia has a new favorite toy she can carry around.

What it does

Tic Tac Toe Set is a great toy itself but it's all about presentation too. Especially if you want to give this as a gift. I made a tag (picture below) and I attached it to the "fabric board". I simply tied one corner of fabric with rope and I attached this tag to the other end.

How we built it

Using java language, we created a code.. package aoops; import java.util.*;

public class project {

static String[] board;
static String turn;


// CheckWinner method will
// decide the combination
// of three box given below.
static String checkWinner()
{
    for (int a = 0; a < 8; a++) {
        String line = null;

        switch (a) {
        case 0:
            line = board[0] + board[1] + board[2];
            break;
        case 1:
            line = board[3] + board[4] + board[5];
            break;
        case 2:
            line = board[6] + board[7] + board[8];
            break;
        case 3:
            line = board[0] + board[3] + board[6];
            break;
        case 4:
            line = board[1] + board[4] + board[7];
            break;
        case 5:
            line = board[2] + board[5] + board[8];
            break;
        case 6:
            line = board[0] + board[4] + board[8];
            break;
        case 7:
            line = board[2] + board[4] + board[6];
            break;
        }
        //For X winner
        if (line.equals("XXX")) {
            return "X";
        }

        // For O winner
        else if (line.equals("OOO")) {
            return "O";
        }
    }

    for (int a = 0; a < 9; a++) {
        if (Arrays.asList(board).contains(
                String.valueOf(a + 1))) {
            break;
        }
        else if (a == 8) {
            return "draw";
        }
    }

// To enter the X Or O at the exact place on board.
    System.out.println(
        turn + "'s turn; enter a slot number to place "
        + turn + " in:");
    return null;
}

// To print out the board.
/* |---|---|---|
| 1 | 2 | 3 |
|-----------|
| 4 | 5 | 6 |
|-----------|
| 7 | 8 | 9 |
|---|---|---|*/

static void printBoard()
{
    System.out.println("|---|---|---|");
    System.out.println("| " + board[0] + " | "
                    + board[1] + " | " + board[2]
                    + " |");
    System.out.println("|-----------|");
    System.out.println("| " + board[3] + " | "
                    + board[4] + " | " + board[5]
                    + " |");
    System.out.println("|-----------|");
    System.out.println("| " + board[6] + " | "
                    + board[7] + " | " + board[8]
                    + " |");
    System.out.println("|---|---|---|");
}

public static void main(String[] args)
{
    Scanner in = new Scanner(System.in);
    board = new String[9];
    turn = "X";
    String winner = null;

    for (int a = 0; a < 9; a++) {
        board[a] = String.valueOf(a + 1);
    }

    System.out.println("Welcome to 3x3 Tic Tac Toe.");
    printBoard();

    System.out.println(
        "X will play first. Enter a slot number to place X in:");

    while (winner == null) {
        int numInput;

    // Exception handling.
    // numInput will take input from user like from 1 to 9.
    // If it is not in range from 1 to 9.
    // then it will show you an error "Invalid input."
        try {
            numInput = in.nextInt();
            if (!(numInput > 0 && numInput <= 9)) {
                System.out.println(
                    "Invalid input; re-enter slot number:");
                continue;
            }
        }
        catch (InputMismatchException e) {
            System.out.println(
                "Invalid input; re-enter slot number:");
            continue;
        }

        // This game has two player x and O.
        // Here is the logic to decide the turn.
        if (board[numInput - 1].equals(
                String.valueOf(numInput))) {
            board[numInput - 1] = turn;

            if (turn.equals("X")) {
                turn = "O";
            }
            else {
                turn = "X";
            }

            printBoard();
            winner = checkWinner();
        }
        else {
            System.out.println(
                "Slot already taken; re-enter slot number:");
        }
    }

    // If no one win or lose from both player x and O.
    // then here is the logic to print "draw".
    if (winner.equalsIgnoreCase("draw")) {
        System.out.println(
            "It's a draw! Thanks for playing.");
    }

    // For winner -to display Congratulations! message.
    else {
        System.out.println(
            "Congratulations! " + winner
            + "'s have won! Thanks for playing.");
    }
}

}

Challenges we ran into

What is the challenge of Tic Tac Toe? The #tictactoe challenge has gained quite the popularity on the video-sharing app. The videos work this way. A checkerboard is drawn on a sheet of paper and the boxes are filled with treats. And then the participants are introduced - they are none other than pets.

Accomplishments that we're proud of

Certainly I am proud of designing a game, but I still wait for the first real professional achievement of my life. Applying for a job in your gaming, I hope to get a chance to work on some big campaigns, to have some impact in my work, and maybe to achieve a positive change in the world.

What we learnt

designing an gaming application using java

What's next for Tic-Tac-Toe

Tic Tac Toe—it's so simple, yet endlessly entertaining. But did you know that there's a mathematically proven strategy to follow that can help you win, or at least draw, every time you play? That's right; you never have to lose a game of Tic Tac Toe again, and we'll teach you exactly how. Keep reading to learn how to always win at Tic Tac Toe using a foolproof strategy.

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