posted an update

Try these proofs!

( A → B ) ( S → ¬ N ) ( K ∧ S ) ( ¬ N → ( K ↔ G ) ) Target: ( G ∧ ¬ N )

( ¬ A ∧ B ) ( ¬ A → ( C → D ) ) ( C ∧ S ) ( D → P ) ( P → J ) target: ( ¬ A ∧ J )

( A → B ) ( S → ¬ N ) ( K ∧ S ) ( ¬ N → ( K → G ) ) Target: G

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